ASQ Calibration Technician Certification Practice Test

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $9.99Unlock all
Session length

1 / 20

What is the amount of power being dissipated by a light bulb with 87.4 V voltage drop and 1.32 A current?

80 W

100 W

115 W

To determine the amount of power being dissipated by the light bulb, you can use the formula for electrical power, which is given by:

Power (P) = Voltage (V) x Current (I)

In this case, the voltage drop across the light bulb is 87.4 volts, and the current flowing through it is 1.32 amperes. By substituting these values into the formula, you can calculate the power dissipation:

P = 87.4 V x 1.32 A.

When you perform the multiplication, the result is approximately 115.1 watts. This is rounded to 115 watts, which corresponds with the choice labeled as 115 W.

Thus, the correct answer correctly reflects the calculated power dissipated by the light bulb based on the specified voltage and current.

Get further explanation with Examzify DeepDiveBeta

130 W

Next Question
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy